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CA Foundation P3 · Chapter 15 · Question 8 of 9

Machines A and B produce 60% and 40% of a factory's output. 2% of A's output and 5% of B's output is defective. An item chosen at random is found defective. The probability that it was produced by machine B is:

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Reveal answer & explanation

Correct answer: A) 0.625

Explanation

By Bayes' theorem: P(D|A)P(A) = 0.02 x 0.6 = 0.012 and P(D|B)P(B) = 0.05 x 0.4 = 0.020. Total P(D) = 0.032. P(B|D) = 0.020/0.032 = 0.625. 0.375 is P(A|D), and 0.032 is the total probability of a defective item.

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