CA Foundation P3 · Chapter 16 · Question 8 of 9
For a Poisson variable X, P(X = 1) = P(X = 2). Using e⁻² = 0.1353, P(X = 3) is (to four decimals):
Test yourself: pick an answer
Reveal answer & explanation
Correct answer: B) 0.1804
Explanation
e⁻ᵐ m = e⁻ᵐ m²/2 gives m = 2. P(X = 3) = e⁻² 2³/3! = 0.1353 x 8/6 = 0.1353 x 1.3333 = 0.1804. 0.2707 is P(X = 1) = P(X = 2), and 0.0902 is P(X = 4).
More Theoretical Distributions MCQs
- Q1For a binomial distribution with n = 10 and p = 0.4, the variance is:
- Q2The mean and variance of a binomial distribution are 6 and 4 respectively. The number of trials n is:
- Q3A fair coin is tossed 4 times. The probability of getting exactly 2 heads is:
- Q4A Poisson variable X has mean 2. Using e⁻² = 0.1353, P(X ≥ 1) is:
- Q5The standard deviation of a Poisson distribution is 3. Its mean is: