CA Foundation P3 · Chapter 2 · Question 2 of 9
The roots of the equation x² − 11x + 28 = 0 are:
Test yourself: pick an answer
Reveal answer & explanation
Correct answer: D) 4 and 7
Explanation
We need two numbers with sum 11 and product 28: 4 and 7. So x² − 11x + 28 = (x − 4)(x − 7) = 0, giving x = 4 or x = 7. The pair 2 and 14 has product 28 but sum 16.
More Equations MCQs
- Q4The roots of the equation 2x² + 5x + 4 = 0 are:
- Q5The quadratic equation whose roots are 3 + √2 and 3 − √2 is:
- Q6The solution of the simultaneous equations 3x + 4y = 26 and 5x − 2y = 13 is:
- Q7A cashier has ₹1,200 made up of 90 notes, some of ₹10 and the rest of ₹20. The number of ₹20 notes is:
- Q8One root of x³ − 6x² + 11x − 6 = 0 is 1. The other two roots are: