CA Foundation P3 · Chapter 8 · Question 5 of 9
The profit function of a firm is P = −2x² + 120x − 500 (in ₹). The maximum profit is:
Test yourself: pick an answer
Reveal answer & explanation
Correct answer: C) ₹1,300
Explanation
dP/dx = −4x + 120 = 0 gives x = 30, and d²P/dx² = −4 < 0 confirms a maximum. P(30) = −2(900) + 3,600 − 500 = −1,800 + 3,600 − 500 = ₹1,300. Ignoring the sign of −2x² gives ₹4,900.
More Basic Applications of Differential and Integral Calculus in Business and Economics MCQs
- Q7The value of the definite integral ∫ from 1 to 3 of (2x + 1) dx is:
- Q8The demand function for a product is q = 100 − 2p. The price elasticity of demand (in absolute value) at p = 20 is:
- Q9The marginal revenue function of a firm is MR = 50 − 4x. The corresponding demand (average revenue) function is:
- Q1The derivative of y = x⁵ + 3x² − 7 with respect to x is:
- Q2The derivative of x²eˣ with respect to x is:
