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PRC-2 · Chapter 1 · Question 19 of 45

A father distributes Rs. 2,000 amongst his three daughters in such a way that each one of them receives at least Rs. 200. What is the maximum possible mathematical difference between the amounts received by any two daughters?

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Reveal answer & explanation

Correct answer: A) Rs. 1,400

Explanation

To maximize the difference, one daughter must receive the absolute maximum while the others receive the absolute minimum. The two minimums are Rs. 200 each (total Rs. 400). The maximum one can receive is 2,000 - 400 = 1,600. The difference is 1,600 - 200 = Rs. 1,400.

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