PRC-2 · Chapter 1 · Question 19 of 45
A father distributes Rs. 2,000 amongst his three daughters in such a way that each one of them receives at least Rs. 200. What is the maximum possible mathematical difference between the amounts received by any two daughters?
Test yourself: pick an answer
Reveal answer & explanation
Correct answer: A) Rs. 1,400
Explanation
To maximize the difference, one daughter must receive the absolute maximum while the others receive the absolute minimum. The two minimums are Rs. 200 each (total Rs. 400). The maximum one can receive is 2,000 - 400 = 1,600. The difference is 1,600 - 200 = Rs. 1,400.
More Linear And Quadratic Equations MCQs
- Q21A company's revenue function is R = 60x and its cost function is C = 25x + 14,000. At what production level 'x' does the company break even?
- Q22What is the discriminant of the quadratic equation 3x^2 - 4x + 2 = 0?
- Q23What is the sum of the roots for the quadratic equation 2x^2 - 10x + 12 = 0?
- Q24What is the product of the roots for the quadratic equation 2x^2 - 10x + 12 = 0?
- Q25Find the values of x and y in the following simultaneous linear equations: 3x - 2y = 8 and x + y = 6.
