PRC-2 · Chapter 3 · Question 29 of 45
A worker saves Rs. 500 in month 1 and commits to increasing the savings by Rs. 200 every single month thereafter. What is the total cumulative amount saved after exactly 12 months?
Test yourself: pick an answer
Reveal answer & explanation
Correct answer: C) Rs. 19,200
Explanation
This forms an arithmetic series where a = 500, d = 200, and n = 12. Sum = (n/2)[2a + (n-1)d] = (12/2)[1000 + (11)200] = 6(1000 + 2200) = 6(3200) = Rs. 19,200.
More Mathematical Progression MCQs
- Q31In an Arithmetic Progression (AP), the difference between any two consecutive terms is always:
- Q32What is the standard formula for the n-th term (Tn) of an Arithmetic Progression?
- Q33In a Geometric Progression (GP), the ratio between any two consecutive terms is always:
- Q34What is the standard formula for the n-th term (Tn) of a Geometric Progression?
- Q35The sum of the first 10 terms of an AP starting with 2 and having a common difference of 3 is: