CA Foundation P3 · Chapter 7 · Question 8 of 9
The function f(x) = kx + 1 for x ≤ 2 and f(x) = 3x − 1 for x > 2 is continuous at x = 2. The value of k is:
Test yourself: pick an answer
Reveal answer & explanation
Correct answer: A) 2
Explanation
For continuity, the left limit, right limit and f(2) must be equal. Left value: 2k + 1. Right limit: 3(2) − 1 = 5. So 2k + 1 = 5 and k = 2.
More Sets, Relations and Functions, Basics of Limits and Continuity of Functions MCQs
- Q1The number of proper subsets of the set A = {1, 2, 3, 4} is:
- Q2In a group of 200 people, 120 drink tea, 90 drink coffee and 40 drink both. The number of people who drink neither tea nor coffee is:
- Q3The relation R = {(1, 1), (2, 2), (3, 3), (1, 2)} on the set {1, 2, 3} is:
- Q4If f(x) = 2x + 3 and g(x) = x², then (f∘g)(2) is:
- Q5The inverse of the function f(x) = (3x − 5)/2 is: