CA Foundation P3 · Chapter 7 · Question 3 of 9
The relation R = {(1, 1), (2, 2), (3, 3), (1, 2)} on the set {1, 2, 3} is:
Test yourself: pick an answer
Reveal answer & explanation
Correct answer: C) Reflexive and transitive but not symmetric
Explanation
R contains (1,1), (2,2), (3,3), so it is reflexive. It is not symmetric because (1, 2) ∈ R but (2, 1) ∉ R. For transitivity, the only chains are (1,1),(1,2) → (1,2) and (1,2),(2,2) → (1,2), both in R, so it is transitive. Hence it is not an equivalence relation.
More Sets, Relations and Functions, Basics of Limits and Continuity of Functions MCQs
- Q5The inverse of the function f(x) = (3x − 5)/2 is:
- Q6The value of lim (x→3) (x² − 9)/(x − 3) is:
- Q7The value of lim (x→∞) (4x² + 3x)/(2x² − 7) is:
- Q8The function f(x) = kx + 1 for x ≤ 2 and f(x) = 3x − 1 for x > 2 is continuous at x = 2. The value of k is:
- Q9If A has 3 elements and B has 5 elements, the number of one-one functions from A to B is: